So, a hexa-flexagon is topologically equivalent to a Mobius Strip with 3 half-twist. Does this hold for a hexa-hexa-flexagon and higher order hexa-flexagons? How the heck do you unravel these and prove how many twist?
2026-03-25 19:06:01.1774465561
Number of half-twist for higher order hexa-flexagons
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From what I've observed, the equation is 3n-6, where n is the number of faces. For every face that is added onto the original tri-hexaflexagon, more of the paper needs to stay "hidden" under half-twists, so 3 twists are added to hide the 3 sections of the new face.
Note that I've only observed hexaflexagons up to order 7, with the rest being my reasoning.