I am given the following:
$z = g(u, v)$
$u = u(x, y, t)$
$v = v(x, y, t)$
$x = x(t)$
$y = y(t)$
And I need to find the number of terms for $dz/dt$ (using the chain rule)
Drawing out a tree I have...
z
/ \
u v
/ | \ / | \
x y t x y t
| | | |
t t t t
Applying the chain rule, I believe the terms would be...
${dz\over{du}} \times {du\over{dx}} \times {dx\over{dt}} + {dz\over{du}} \times {du\over{dy}} \times {dy\over{dt}} + {dz\over{du}} \times {du\over{dt}} + {dz\over{dv}} \times {dv\over{dx}} \times {dx\over{dt}} + {dz\over{dv}} \times {dv\over{dy}} \times {dy\over{dt}} + {dz\over{dv}} \times {dv\over{dt}}$
Are there 6 terms here?
Yes, this is correct (now, after the last edit): by the Chain Rule, there are indeed $6$ terms there. And your expression is pretty much correct too, except for inaccurate notation: for functions of several variables, their derivatives in this expression must be partial derivatives. So it must look as: $${\partial z\over{\partial u}} \times {\partial u\over{\partial x}} \times {dx\over{dt}} + {\partial z\over{\partial u}} \times {\partial u\over{\partial y}} \times {dy\over{dt}} + {\partial z\over{\partial u}} \times {\partial u\over{\partial t}} + {\partial z\over{\partial v}} \times {\partial v\over{\partial x}} \times {dx\over{dt}} + {\partial z\over{\partial v}} \times {\partial v\over{\partial y}} \times {dy\over{dt}} + {\partial z\over{\partial v}} \times {\partial v\over{\partial t}}$$