A number which is equal to the sum of the squares of its prime factors with multiplicity:
- $16=2^2+2^2+2^2+2^2$
- $27=3^2+3^2+3^2$
Are these the only two such numbers to exist?
There has to be an easy proof for this, but it seems to elude me.
Thanks
A number which is equal to the sum of the squares of its prime factors with multiplicity:
Are these the only two such numbers to exist?
There has to be an easy proof for this, but it seems to elude me.
Thanks
On
Giorgos Kalogeropoulos has found 3 such numbers, each having more than 100 digits.
You can find these numbers if you follow the links in the comments of OEIS A339062 &
A338093
or here https://www.primepuzzles.net/puzzles/puzz_1019.htm
So, such numbers exist! It is an open question if there are infinitely many of them...
Here is a suggestion:
For a start one could investigate under which assumptions about the sizes of $n$ and real variables $x_k\geq2$ $\>(1\leq k\leq n)$ an equality $$\prod_{k=1}^n x_k=\sum_{k=1}^n x_k^2$$ is at all possible.