Odd use of determinants in a product related to a problem of analytical geometry

112 Views Asked by At

This is from R.M.Khan's Analytical Geometry:

From R.M.Khan's Analytical Geometry

Why did the author consider using the determinant in such particular way?

And what is the product this is referring to? It is not the usual matrix multiplication.

Can someone name the concepts used by the writer?

1

There are 1 best solutions below

15
On BEST ANSWER

The author has considered the product :

$\begin{vmatrix} 2l_{ 1 }l_{ 2 } & { l_{ 1 }m_{ 2 }+l_{ 2 }m_{ 1 } } & l_{ 1 }n_{ 2 }+l_{ 2 }n_{ 1 } \\ l_{ 1 }m_{ 2 }+l_{ 2 }m_{ 1 } & 2m_{ 1 }m_{ 2 } & m_{ 1 }n_{ 2 }+m_{ 2 }n_{ 1 } \\ l_{ 1 }n_{ 2 }+l_{ 2 }n_{ 1 } & m_{ 1 }n_{ 2 }+m_{ 2 }n_{ 1 } & 2n_{ 1 }n_{ 2 } \end{vmatrix}$ (Let us name it $D$)

$= \begin{vmatrix} l_ 1 & l_2 & 0 \\ m_1 & m_2 & 0 \\ n_1 & n_2 & 0 \end{vmatrix}$ $(D_1)$ $\times$ $\begin{vmatrix} l_{ 2} & l_{ 1 } & 1 \\ m_{ 2 } & m_{ 1 } & 1 \\ n_{ 2 } & n_{ 1 } & 1 \end{vmatrix}$ $(D_2)$

Just in order to prove the condition required.

Here $0$ is used in first determinant to make the product equal to required condition determinant.No other concept.Just mathematical adjustment.

If some variables $a,b,c,f,g,h$

Satisfy the condition :

$l_1l_2=a , l_1m_2+l_2m_1=2h , m_1m_2=b , l_1n_2+l_2n_1=2g, m_1n_2+m_2n_1=2f,n_1n_2=c$

for two st.lines $l_1x+m_1y+n_1$ and $l_2x+m_2y+n_2$.

Then the equation :

$ax^2+2hxy+by^2+2gx+2fy+c=0$

must represent a pair of st. lines.

Or viceversa, If the equation $ax^2+2hxy+by^2+2gx+2fy+c=0$ represents a pair of st. line than $a,b,c,f,g,h$ must satisfy

$\begin{vmatrix} a & h & g \\ h & b & f \\ g & f & c \end{vmatrix}=0$

Beacuse, since they represent pair of st. lines , they must satisfy

$l_1l_2=a , l_1m_2+l_2m_1=2h , m_1m_2=b , l_1n_2+l_2n_1=2g, m_1n_2+m_2n_1=2f,n_1n_2=c$

for two st.lines $l_1x+m_1y+n_1$ and $l_2x+m_2y+n_2$.

and the determinant $D$ can be written as $D_1 \times D_2$

Where $|D_1|=0$ . Hence $|D|$ also must be $=0$

P.S. : Someone might think that first determinant is multiplied to transpose of second determinant.No.There are several ways to multiply two determinants.Namely :

  • Row by Row

  • Column by Row

  • Row by Column

  • Column by Column

The result is basically the same in all.

Since, in matrix multiplication, we can use only Row by Column procedure, and many people use the same in determinant multiplication too this multiplication of determinants seems to be weird.So, there is nothing wrong or weird here as, may be, the author of this book has practice to multiply determinants Row by Row.