On a hyperbola, find the point on the hyperbola that is distanced 3 times further from one asymptote than the other.

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The equation of the hyperbola is $\ \frac{x^2}{64} - \frac{y^2}{36}=1$

So that means I have the asymptote formulas as well since I can get a and b easily out of the hyperbola equation. I then use the formula for distance, made a ratio for one to be 3 times bigger than the other and I get that the points cordinates are ratioed $\ 12x = -15y $.

I am stuck after that. Any tips?