Customers are going inside a store, the first customer whose birthday matches the birthday of someone that has already entered the store will get a bonus discount. Where on the line to stand to get the biggest chance to win a bonus?
2026-03-27 21:04:38.1774645478
On which place should you stand in a line, to get a bonus.
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I will use an year with $N=365$ days, every day being equally probable as a birthday for each of the customers in the line.
The $k$.th customer has a chance to get the price equal to $p_k$, say, as a matter of notation. Then $p_k$ is combinatorially obtained by counting the day configurations $(d_1, \dots,d_{k-1},d_k)$ with different values on the first $(k-1)$ places, and with $d_k$ repeating one of these $(k-1)$ places, and we divide by the number $N^k$ of all day configurations with $k$ places, so
Corrected version, thanks lulu and Daniel Schepler
$$ \begin{aligned} p_1 &=0\ ,\\ p_2 &=\frac 1N\ ,\\ &\qquad\text{ and for }k\ge 3\\ p_k &= \frac 1{N^k}\cdot N(N-1)\dots(N-k+2)\cdot(k-1) \\ &= \left(1-\frac 1N\right) \dots \left(1-\frac {k-2}N\right)\cdot \frac {k-1}N\ . \end{aligned} $$ The maximal value is in the script below obtained for $k=20$,
p(20) ~ 0.0323198575Here is numerically the list of the probabilities for the first customers:
sage code was used.