If I have the figure below, how can I get the angle $a_2$ (the angle is >0 in counterclockwise direction)?
$$a_2 = \frac{\pi}{2} + a_1$$
or
$$a_2 = \frac{\pi}{2} - a_1$$ ?
Thank you for your help.
If I have the figure below, how can I get the angle $a_2$ (the angle is >0 in counterclockwise direction)?
$$a_2 = \frac{\pi}{2} + a_1$$
or
$$a_2 = \frac{\pi}{2} - a_1$$ ?
Thank you for your help.
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We have $$|-\alpha_1| + \alpha_2 = \frac{\pi}2$$
since $$\alpha_2 = \frac{\pi}2 - |-\alpha_1|= \frac{\pi}2 - |\alpha_1|= \frac{\pi}2 - \alpha_1$$