The question is: find $\delta \le \omega_1$ and $\rho \lt \omega$ such as $\omega_1 = \omega \cdot \delta + \rho$. My guess is that $\delta = \omega_1$ and $\rho = 0$, abut I don't know how to prove it.
2026-03-27 08:16:57.1774599417
Ordinal arithmetic question
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HINT: Prove that if $\alpha,\beta,\gamma$ are countable ordinals, then $\alpha\cdot\beta+\gamma$ is a countable ordinal.