A circle is inscribed into the rhombus ABCD with one angle 60. The distance from the centre of the circle to the narest vertex is equal to 1. If P is any point of the circle ,then $$(PA)^2 + (PB)^2 +(PC)^2 + (PD)^2$$ is equal to?
2026-03-29 21:39:27.1774820367
(PA)^2 + (PB)^2 +(PC)^2 + (PD)^2 is equal to?
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