How do I find the generating function for partitions of $n$ that have no part with size $2$? In general, how would I find this for partitions that have no part of size $k$?
2026-03-26 17:52:16.1774547536
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Partitions without 2
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The generating function for $p(n)$ is
$$p(n)=\prod_{k\ge 1}\frac1{1-x^k}=\prod_{k\ge 1}\sum_{j\ge 0}x^{jk}\;:$$
the coefficient of $x^n$ is the number of ways to write $n$ in the form
$$n=j_1\cdot1+j_2\cdot2+j_3\cdot3+\ldots\;.$$
To omit $\ell$ as a summand in the partitions, drop out the factor of $\dfrac1{1-x^\ell}$. Thus, if $p_\ell(n)$ is the desired generating function, you have
$$p_\ell(n)=(1-x^\ell)p(n)\;.$$
Are objects identical or distinct?
If they are distinct, it may help to think of recursion. Suppose we let S(n, t, r) be the number of partitions of n objects into t partitions out of which r partitions have only 1 object. Then
S(n, t, r) = (t-r)S(n-1, t, r) + S(n-1, t-1, r-1)
This is a similar recursion to Stirling numbers of the second kind, and hope this gets you started.