Path-connected implies continuous?

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  1. At the beginning of proof of problem 2, The author choose arbitrary a in (0,1) and

Claimed that there exists some closed interval [a1,a2] containing a.

I know this is right, but I'm curious that this is always guranteed or is just specific case.

Is it possible for some open sets not to have a compact subset (except singleton) ?

  1. The author showed that f is continuous on [a1,a2] and this set is arbitrary.

But does it gurantee that if f is continuous on all of such compact sets, then it follows that f is continuous on open set such as (0,1)? Doesn't exist some point of (0,1) not in such compact sets?

I think this questions can be summarized as can open set be expressed as an union of compact sets?

If I missed something, could you point it out?

It will be very helpful to solidate my understading about elementary topology.

Thank you for your answer in advance.