Plotting $θ(x+2)+θ(x+1)+θ(x)x$

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The unit step function is given in a combinatory form $θ(x+2)+θ(x+1)+θ(x)x$

, so what we have here is:

for $x< 0$:

$θ(x+2)=1 \ \ \ when \ \ -2<x$

$θ(x+1)=1 \ \ \ when \ \ -1< x$

$θ(x)x=0 $

Then for $x> 0$:

$θ(x+2)=1 \ \ \ when \ \ -2<x$

$θ(x+1)=1 \ \ \ when \ \ -1< x$

$θ(x)x=x $

So I thought we would get a straight horizontal line for $x<0$ at y=1, and then $y=x+1$ from $x>0$.

But wolfram plots this https://www.wolframalpha.com/input?i=%CE%B8%28x%2B2%29%2B%CE%B8%28x%2B1%29%2B%CE%B8%28x%29x

Why, and is my assumption not correct?

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If we plot the Heaviside Unit Step, $\theta(x)$, we get

enter image description here

If we now plot $\theta(x+2)$, this is just shifting the previous by two to the left, we get

enter image description here

If we plot, $θ(x+2)+θ(x+1)$, notice how we get a unit step at $-2$, but also get one at $-1$

enter image description here

If we plot, $θ(x+2)+θ(x+1)+θ(x)x$, notice how we have the unit step at $-2$, then $-1$ and then $0$. Since it is $1$ at $x \ge 0$, notice how it is just the line $x$ to the right.

enter image description here