Plotting the graph of $\operatorname{Re}(z)<2$

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$$\operatorname{Re}(z)<2$$

My idea was that, in the complex plane, the graph looks like a ray starting at the origin and extending up to $2$, but not including that point. Then there would have to be a little comment or some way to indicate that this applies to every angle $\theta$ around the origin, so long as the radius, $R$, is less than $2$.

However, Wolfram plots it like this. Which one of us is more correct? I don't understand why Wolfram plots this in the $x$-$y$ axis.

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Neither is correct.

With $z = x+iy$, the inequality is just $x < 2$, representing a half-plane to the left of the vertical line $x = 2$:

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