The inverse of the function $y=2^x$ is
$\bf (A)$ $y=\log_2x\quad{\bf (B)}\, y=-2^x\quad{\bf (C)}\,y=2^{-x}\quad{\bf (D)}\,y=x^2.$
Need help solving this problem and plotting it on a graph.
The inverse of the function $y=2^x$ is
$\bf (A)$ $y=\log_2x\quad{\bf (B)}\, y=-2^x\quad{\bf (C)}\,y=2^{-x}\quad{\bf (D)}\,y=x^2.$
Need help solving this problem and plotting it on a graph.
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The answer is $log_2(x)$, by definition. The graph is a reflection of the graph of the original function, as WolframAlpha will show you: