pointwise convergence definition

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I need some help to clarify with the idea of pointwise convergence.

The condition for pointwise convergence is usually given that if the limit of $f_n$ exists for each $x$ $\in$ $A$.

In Stephen Abbott's Understanding Analysis book, to show comparison with uniform convergence, the pointwise convergence definition is given as: " $f_n$ converges pointwise on $A$ to a limit function $f$ defined on $A$ if, for every $\epsilon>0$ and $x$ $\in$ $A$, there exists an $N$ $\in$ $\mathbb{N}$ (can be dependent on $x$) such that $|f_n(x)-f(x)|<\epsilon$ whenever $n$ $\geq$ $N$."

Taking an example of $x/(x+n)$, $x\geq0$, we can see the limit is $0$ holds for all $x\geq0$, but when evaluating it in terms of finding epsilon, $|f_n(x)-f(x)|$ can only be bounded with $\epsilon\geq1$, isn't this contradict with the book's definition? but how can we explain the condition of limit exists? Does this example have pointwise convergence after all?

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The difference between pointwise and uniform convergence is that the choice of $N \in \mathbb N$ depends on the choices of both $x$ and $\varepsilon$ in the case of pointwise convergence, while it only depends on $\varepsilon$ in the case of uniform convergence. That is, in the case of uniform convergence, there will exist an $N$ for each $\varepsilon$ such that convergence is “uniform” (or $N$ is the same) for each $x$.

In your example, only pointwise convergence is possible, since the choice of $N$ will always depend on both $x$ and $\varepsilon$.