I know that for some functions, for instance $f(x) = e^{-x^2}$, there does not exist a primitive.
Does there is a primitive for the function $f(x) = \frac{\operatorname{sin}(x)}{x}$?
I know that for some functions, for instance $f(x) = e^{-x^2}$, there does not exist a primitive.
Does there is a primitive for the function $f(x) = \frac{\operatorname{sin}(x)}{x}$?
Copyright © 2021 JogjaFile Inc.
No It is not In terms of elementary functions, But we can write in Infinite Series form.
Using $$\displaystyle \sin x= x-\frac{x^3}{3!}+\frac{x^5}{5!}-\frac{x^7}{7!}+..........$$
So $$\displaystyle \frac{\sin x}{x} = 1-\frac{x^2}{3!}+\frac{x^4}{4!}-\frac{x^6}{6!}.........$$
So $$\displaystyle \int \frac{\sin x}{x}dx = \int \left\{1-\frac{x^2}{3!}+\frac{x^4}{4!}-\frac{x^6}{6!}.........\right\}dx$$