I have to calulate two probabilities from convolution of generating function, $P(X_1+X_2...+X_n = k)$
$P(X_1+X_2...+X_n > k)$
Where $X_i \in (1,2...m)$(probability is 1/m)
how should i start it in case when we have digits i would make something like this:
$(\sum_{i=0}^{9}x_i)^n$
and then take argument before x^k and divide it by n^10.