The problem is based on picking 2 people of 100.All 100 have badges with their numbers.Whats the probability of those 2 the smallest being bigger or equal to 80?
I believe its 20C2/100C2 is this right?
The problem is based on picking 2 people of 100.All 100 have badges with their numbers.Whats the probability of those 2 the smallest being bigger or equal to 80?
I believe its 20C2/100C2 is this right?
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In your answer the denominator represents the number of ways to pick the two people out of $100$. The numerator should represents the number of ways to pick two people from the range $80$ to $100$ inclusive (there are $100-80+1=21$ numbers in this range). Hence the answer is $$ {\binom{21}{2}}\biggr/{\binom{100}{2}} $$