probability of a die rolling 6, N times more often than any other number

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I am looking for a way to calculate the possibility of a die rolling 6, at least N rolls more than any other number.

Here is an example:

Let's say I throw a die 100 times and I want to calculate the possibilty that the number 6 appears 20 rolls more than any other number. So for example these could be the roll results:

6: 40x

5: 20x

4: 10x

3: 15x

2: 10x

1: 5x

So the 6 was rolled 20 rolls more than the 5.

Here is another example:

6: 50x

5: 10x

4: 30x

3: 10x

2: 0x

1: 0x

Here the 6 was rolled 20 rolls more than the 4. And so on. There must be an enormous number of cases in which this condition is satisfied.

I am looking for help on how to calculate the prbability, that the given condition is satisfied.

Thanks in advance!