I'm trying to solve this on: "from our union we know that 0,01% is ill from some kind of a disease. What is the probability that from a sample of 10 people at least one is ill"
My thinking so far has been something like this (X represents ill people from the sample).
$P(X\geq 1) = 1-P(X<1)^c = 1- (\frac{0,01}{100})^c \approx 9,995*10^{-4} $
Please tell me if I am like totally wrong, right ore something in between. All the possible feedback is welcomed
The probability that at least one person in the sample is equal to one minus the probability none are ill. If the samples are independent that that probability is $(1-0.001)^{10}$ so subtract that from $1$.