How can I compute $P(X>2Y)$ which is exponential distribution. Where $X$ follows exponential distribution with $\lambda = 0.3$ and $Y$ follows exponential distribution with $\lambda = 0.6$. While X & Y are independent. Here's where i am stuck at $=1-P(X<2Y)$ Can someone please help me with it?
2026-03-25 09:23:31.1774430611
Probability of exponential distribution
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Hint:
If $Y$ has exponential distribution with parameter $0.6$ then $2Y$ has exponential distribution with parameter $0.3$ (just like $X$, now apply symmetry).