I have four sided die with a number on each side $\ (1,2,3,4) $ and I need to calculate the possibility of getting $\ 3 $ at least twice after throwing the die $\ 5$ times.
So I out of the $\ 5 $ times I should pick 2 where $\ 3$ is the outcome and then I have $\ 3 $ throws left to have whatever outcome. so it should be $\ \frac{ {5 \choose 2} \cdot 4^3}{4^5} $
Where am I wrong?