Probability of increasing order of a $3$ rolls of a die.

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A six-sided die is rolled three times. What is the probability that the value of every next roll is greater than the value of the previous one?

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So the total possible rolls of the dice are $6^3$. Among these the way to see the cases in which the numbers are "strictly" increasing are choose any three numbers then there is one case corresponding to it.

Therefore the probability is $$\frac{^6C_3}{6^3}=\frac{5}{54}$$