Here's a problem from my probability book:
The chance of throwing $14$ is greater with three dice than with five as $54$ to $49$.
Unfortunately, I got that the chance of both is the same! So where did I go wrong? Let me show my work:
Let's first do three dice:
- $662$: $3$ possibilities
- $653$: $6$ possibilities
- $644$: $3$ possibilities
- $554$: $3$ possibilities
Adding them up, we have$${{3 + 6 + 3 + 3}\over{6^3}} = {5\over{72}}$$
Let's next do five dice:
- $65111$: $20$ possibilities
- $64211$: $60$ possibilities
- $63311$: $30$ possibilities
- $63221$: $60$ possibilities
- $62222$: $5$ possibilities
- $55211$: $30$ possibilities
- $54311$: $60$ possibilities
- $54221$: $60$ possibilities
- $53321$: $60$ possibilities
- $54222$: $20$ possibilities
- $44411$: $10$ possibilities
- $44321$: $60$ possibilities
- $44222$: $10$ possibilities
- $43331$: $20$ possibilities
- $43322$: $30$ possibilities
- $33332$: $5$ possibilities
Adding them up, we have$${{540}\over{6^5}} = {5\over{72}},$$which shouldn't be the case since the two probabilities shouldn't be equal. So where did I overcount in the case of $5$ dice? Or is there a mistake in the problem statement?
There must be a mistake in the problem statement. I've checked with a few lines of python: there are indeed $15$ ways to score exactly $14$ with three dice and $540$ ways with five. I haven't been able to find a plausible way to correct it: changing $14$ to another number, changing "exactly" to "at most", or "less than", all fail to give the claimed ratio.