Two distinct squares are chosen uniformly at random on an $8\times 8$ chessboard, and rooks are placed on these squares. What is the probability that they will attack each other?
Edit : thanks everyone for their concern. I solved it :p. No matter where I place my rook it has 14 squares to go through in order to kill another one so my probability would be 14/63 or 2/9
total options for placing first rook are 64 and second is 63 now in our scenario first rook can be placed at any of $64$ but second must be place in the $14$ affected boxes. answer is $\dfrac {14}{63}$.