Probability proof clarification 2

16 Views Asked by At

Suppose that A and B are two events such that $$P(A) =.8$$ $$P(B) =.7$$

Is it possible that

a) $$P(A\cup B)=.5$$ and that

b)$$P(A \cap B) =.75?$$

Since there is no information on the sets relationships, is it wrong to say that a) "it's possible" and b) "not possible"

... because we know that the lowest it can be is zero and highest value it can be is .7

2

There are 2 best solutions below

0
On BEST ANSWER

Hints

Since $A\subset A\cup B$ it is $P(A)\le P(A\cup B).$

Since $A\cap B\subset B$ it is $P(A\cap B)\le P(B).$

0
On

No. This is because if $C\subseteq D$, then $P(C)\leq P(D)$.

And, of course, because $A\cap B\subseteq B$ and $A\subseteq A\cup B$.