Lola is obsessed by the colour of her hair. On any given day there is an 80% chance she will change the colour of her hair for the next day. Her hair is blond 40% of the time, brown 30% , red 20% and purple for the remainder. Given Lola has red hair on Friday, what is the probability that
- Tomorrow her hair is brown ?
- Her hair is not red on Saturday and Sunday AND her hair is a different colour on Saturday and Sunday.
I have trouble with this probability question, even though I read the answers but I still don't understand their solution. In the solutions for Q1, they simply just wrote $0.8 \times \frac{3}{8}=0.3$, I understand where the $0.8$ came from since there is a 80% chance that she will change her hair. But where did the $\frac{3}{8}$ come from? Thanks.
I think an interesting way to think of your question one is to imagine Lola without hair on Friday. On Saturday we know there is an 80% chance of changing so the first (0.8) is clear. Now if she doesn't have hair, there is a 30% chance of getting brown hair so (0.8)*(0.3) or $\frac{8}{10}$ * $\frac{3}{10}$ which is likely what you originally thought.
However, we know Lola does have hair and red hair at that. Red hair has a 20% chance of occurring so our formula looks like
$\frac{8}{10}$ *$\frac{30}{100-20}$ similarity, $\frac{8}{10}$ *$\frac{30}{40+30+10}$
The 100-20 is really meaning that there was a 100% chance but we've taken off 20% from the total and the 40+30+10 is a sum of all the other probabilities!