Probability to draw one set of marbles before another set

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I have a bag of 15 marbles - 5 white, 10 black.

White wins if 3 white marbles are drawn before 4 black marbles are drawn. Black wins if 4 black marbles are drawn first.

How do I calculate the odds white/black win this game?

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Some thoughts to get you started

White can win in as little as $3$ draws and at most $6$ draws, otherwise we would have had $4$ black marbles drawn before the third white

Black can win in as little as $4$ draws and at most $6$ draws, otherwise we would have had $3$ white marbles drawn before the fourth black.

Notice no game will ever go $7$ draws or more.

So all that needs to be done is to look at the four cases white can win and the three cases black can win and compare the two.