Probability -You roll four 6-sided dice three times

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You roll four $6$-sided dice three times.

What is the probability none of the dice in any roll came up as $4$?

I'm thinking about: $$\left(\left(5/6\right)^4\right)^3\approx 0.1121$$

please let me know,

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Throwing at the same time has no effect if you're looking at the values of individual dice, so it's as if you throw $12$ times with a single die and want no $4$ to occur, which is indeed $\left(\frac{5}{6}\right)^{12}$ as you have.