Problem in understanding proof of Implicit Function Theorem from Calculus of Manifolds

125 Views Asked by At

From the proof of the Implicit Function Theorem given in Spivak's "Calculus of manifolds" page 42, for $f: R^n \times R^m \to R^m$ which is continuously differentiable we define a $F:R^n \times R^m \to R^n\times R^m$ such that $F(x,y)=(x,f(x,y))$ then if $F^\prime(a,b)\neq 0$ for $(a,b)$ contained in $W \subset A\times B$ with $A \subset R^n , B \subset R^m $ then $F:A \times B \to W$ has a differential inverse $h:W\to A\times B$ which is of the form $h(x,y)=(x,k(x,y))$ for some differentiable function $k$ (since $F$ is of this form). What I cannot understand is that why does the function $k$ become differentiable since we haven't proved it.

1

There are 1 best solutions below

0
On BEST ANSWER

It is part of the (multivariate) inverse function theorem that the inverse function of an $F: \>{\mathbb R}^d\to{\mathbb R}^d$ is again differentiable. This part does not come for free; some extra work is needed. This fact immediately implies that your $k$, being the second component of $F^{-1}$, is differentiable.