I am confused on proving that
If a, b, c are 3 numbers in harmonic progression
Then
${(a^n+c^n) /2} >({(a+c)/2}) ^n$
I attempted like this...
Since a, b, c are in hp so
$(a+c) /2>b$
where b is the Harmonic Mean of a and c.
But what next?
I am confused on proving that
If a, b, c are 3 numbers in harmonic progression
Then
${(a^n+c^n) /2} >({(a+c)/2}) ^n$
I attempted like this...
Since a, b, c are in hp so
$(a+c) /2>b$
where b is the Harmonic Mean of a and c.
But what next?
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Assuming that $a,c\ge0$ and $n$ is a positive integer, we have that $x^n$ is a convex function for $x\ge0$.
For any convex function, $f$, $$ \frac{f(a)+f(c)}2\ge f\left(\frac{a+c}2\right) $$