Product matrix and induction

141 Views Asked by At

I am not sure which method to use here. Should I do it for $n=2$ and $n=3$ and then use induction on $n$?

Let $\alpha_1,\alpha_2,\ldots,\alpha_n \in \mathbb{R}$, where $n \geq 2$. Show that $$\left|\begin{array}{ccccc} 1 & \alpha_1 & \alpha_1^2 & \cdots & \alpha_1^{n-1}\\ 1 & \alpha_2 & \alpha_2^2 & \cdots & \alpha_2^{n-1}\\ \vdots & \vdots & \vdots & \ddots & \vdots\\ 1 & \alpha_n & \alpha_n^2 & \cdots & \alpha_n^{n-1} \end{array} \right| = \prod_{1 \leq i < j \leq n}(\alpha_j-\alpha_i).$$

1

There are 1 best solutions below

4
On BEST ANSWER

Nice to see that Warwick are still using this question (link is broken now). In my year most people heard through others that this is called the Vandermonde matrix, and a bunch of proofs for it are found online. I realise that the deadline is today, but do attempt to understand the proofs.

I found the first proof the easiest to understand at the time, but perhaps you'd like to use the second proof to help with your induction.

Good luck!