Proof: Clifford-Algebra representations are semisimple / completely reducible

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There is a theorem: Every finite-dimensional Clifford-Algebra representation $V$ is semisimple / completely reducible, which means that it's a direct sum of irreducible subrepresentations.

How this can be proven? Probably one has to construct to a given irreducible subrepresentation $U \subset V$ another subrepresentation $U' \subset V$, such that $U \oplus U' = V$. How?