Proof for $-4\pi^2+48\ne A+B\pi+C\pi^2$ when $(A,B,C)\ne (48,0,-4)$

Question

I have to prove $-4\pi^2+48\ne A+B\pi+C\pi^2$ when $(A,B,C)\ne (48,0,-4)$
$A,B,C \in \mathbb{Q}$
As a part of question I try to solve.

Answer 1

What will happen if $$(C+4)\pi^2+B\pi+(A-48)=0?$$