Proof of Equality with Mixed Partials

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Here is the link: Hessian

I understand everything but this line: $$g(x_0 + \Delta x) − g(x_0) = \frac{dg}{dx} (ξ) \Delta x$$ i.e., $$S (X_0, \Delta x, \Delta y) = \frac{∂φ}{∂x} (ξ, y_0 + \Delta y) − \frac{∂φ}{∂x} (ξ, y_0)\Delta x$$

$\textbf{Question:}$ Can someone explain how this relation is reached?

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In the link you provided, if you look up a few lines, you'll see $g(x)$ defined as $$g(x)=\phi(x,y_{0}+\Delta y)-\phi(x,y_{0})$$

So to get to the final relation, they just took the partial derivative with respect to $x$, and evaluated at $x=\xi$.

$$S (X_0, \Delta x, \Delta y)=g(x_0 + \Delta x) − g(x_0) = \frac{d(\phi(x,y_{0}+\Delta y)-\phi(x,y_{0}))}{dx}\bigg|_{x=\xi} \Delta x=\left(\frac{\partial\phi}{\partial x} (ξ, y_0 + \Delta y) − \frac{\partial \phi}{\partial x} (ξ, y_0)\right)\Delta x$$