Proof on Rational Numbers

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I am trying to determine whether the following structure forms a Ring under the Real Number Definition of Addition and Multiplication

Consider the set of Real Numbers of the form:

$A = \{a + bp \:|\: a,b \in \mathbb{Q}, p \in \mathbb{R} - \mathbb{Q}\}$ with $p$ being fixed.

And consider the structure $\left(A, +, .\right)$

Where + and . are as defined in the Real Numbers.

It's fairly easy to show that axioms over addition are satisfied and that it forms an Albelian Group.

For multiplication however I don't believe that it's closed.

Taking two elements in $A$ say

$x_{1} = a_{1} + b_{1}p$ and $x_{2} = a_{2} + b_{2}p$

Then

$x_{1} \cdot x_{2} = \left(a_{1}a_{2} + b_{1}b_{2}p^{2}\right) + \left(a_{1}b_{2} + a_{2}b_{1}\right)p$

Now unless I'm interpreting this incorrectly I can only say that it is of the form of A : $x = a + bp \iff p^{2} \in \mathbb{Q}$

If $p^{2} \in \mathbb{R} - \mathbb{Q}$

Then $x$ now takes the form

$x = a + bp_{1} + cp_{2}$ where $a,b,c \in \mathbb{Q}$ and $p_{1}, p_{2} \in \mathbb{R} - \mathbb{Q}$ and $p_{1} \neq p_{2}$

As such I can not conclude that the set A is closed under multiplication unless $p^{2} \in \mathbb{Q}$

Have I missed something here?

Thanks, David

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You haven't missed anything. To be closed under multiplication $p$ should necessarily be a root of a quadratic equation with rational coefficients. (It is called an algebraic number of degree 2).