I need to prove that
$$ x + y = y ~~~\iff~~~ xy = x $$
also need to prove that:
$$ x + y = x ~~~->~~~ x + not(y) = 1 $$
Using algebra boolean properties.
But I have no idea how to solve this problem.
Any ideas? Thanks
I need to prove that
$$ x + y = y ~~~\iff~~~ xy = x $$
also need to prove that:
$$ x + y = x ~~~->~~~ x + not(y) = 1 $$
Using algebra boolean properties.
But I have no idea how to solve this problem.
Any ideas? Thanks
Here's a useful principle for the first problem:
Absorption
$x + xy = x$
$x(x+y) = x$
Applied to your problem 1, going from left to right:
Assume $x + y = y$. Then $xy = x(x+y) = x$
Can you go from right to left?
For the second problem, use:
Complement
$x + x' = 1$
$xx'=0$
and
Annihilation
$x + 1 = 1$
$x0=0$