Prove Euler characteristic satisfies $\chi(X \times Y)=\chi(X)\chi(Y)$ for polyhedra $X$ and $Y$

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Prove that for any topological polyhedra, $X$, $Y$, the product $X \times Y$ has the Euler characteristic $\chi(X \times Y)=\chi(X)\chi(Y)$

I know that for polyhedron $P$ which is homemorphic to a closed surface $S$. If $P$ has $f $ faces, $ e$ edges and $ v$ vertices. Then $\chi(P)=f-e+v $.

I believe that taking the product, still makes the shape a polyhedra, but I am not sure how to count the number of edges, vertices and faces