Prove $\int_{-1}^1 (1-x^2)^n \, dx \ge \frac{1}{\sqrt{n}}$

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$$\int_{-1}^1 (1-x^2)^n \, dx\ge \frac{1}{\sqrt{n}}$$

So, there is a same question about that. Here is the link; Approximating to the identity by polynomials (Terrance Tao Analysis 2 , 3rd ed , page-73, ex.3.8.2)

In that question, integral is separated from different points. Author says that one part of it is greater than $$\frac{4}{3 \, \sqrt{n}}.$$

How one can prove that?