Here is the problem: The only condition given is $DF//BC$, is it possible to prove that $GH//BC$? Please verify it. Any help will be appreciated.

Here is the problem: The only condition given is $DF//BC$, is it possible to prove that $GH//BC$? Please verify it. Any help will be appreciated.

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Yes ! $GH||BC$ Now since $G$ is midpoint of $DE$ and $H$ is midpoint of $EF$.
${\bf Claim}: \bigtriangleup DEF ~\& \bigtriangleup GEH$ are similar
Since $\frac{DE}{GE}=\frac{FE}{HE}$
and $\angle DEF=\angle GEH$.
and therefore from Side-Side-angle similarity theorem both the triangles are similar and hence $GH||BC$.