Prove or disprove:
if $A,B\in M_{n\times n}(F)$ are invertible, and also $A^{-1}B^{-1}AB=cI_n$, $c \in F$ then $c^n=1$.
I think it has to do with multiplying both sides by $A^{-1}B^{-1}$ but I don't know what I can do from there.
Prove or disprove:
if $A,B\in M_{n\times n}(F)$ are invertible, and also $A^{-1}B^{-1}AB=cI_n$, $c \in F$ then $c^n=1$.
I think it has to do with multiplying both sides by $A^{-1}B^{-1}$ but I don't know what I can do from there.
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HINT
Take a determinant from both sides of the equation.
Remember: $\det(AB)=\det(A) \det(B)$, $\det(I)=1$ and $\det(cA)=c^n \det(A)$.