Prove that $\{C_n\}_{n\in\mathbb{Z}}$ is a chain complex with boundary homomorphism $\partial:=\bigoplus_{\alpha\in\Lambda}\partial^{\alpha} $.

66 Views Asked by At

Let $\Lambda $ be a fixed set. For each $\alpha\in\Lambda $ is $\{C_n^{\alpha}\}_{n\in\mathbb{Z}}$ a chain complex with boundary homomorphism $\partial^{\alpha}$.

For each $n\in\mathbb{Z}$ we define $C_n=\bigoplus_{\alpha\in\Lambda}C_n^{\alpha} $. Prove that $\{C_n\}_{n\in\mathbb{Z}}$ is a chain complex with boundary homomorphism $\partial:=\bigoplus_{\alpha\in\Lambda}\partial^{\alpha} $.

To show that $\{C_n\}_{n\in\mathbb{Z}}$ is a chain complex with boundary homomorphism $\partial$, we have to prove that $\partial\circ\partial=0$. For this, let's take $(x_{\alpha})\in C_n$ so $(\partial\circ\partial)(x_{\alpha})=\partial(\partial(x_{\alpha}))=\partial((\partial^{\alpha}(x_{\alpha})))=(\partial^{\alpha}(\partial^{\alpha}(x_{\alpha})))=((\partial^{\alpha}\circ\partial^{\alpha})(x_{\alpha}))=(0)$. Is this demonstration okay? What can be improved? Is there another way to do this?

1

There are 1 best solutions below

0
On BEST ANSWER

This community wiki solution is intended to clear the question from the unanswered queue.

Yes, your proof is correct.