Prove that every integer n≥12 is the sum of two composites.

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Prove that any natural number greater than or equal to 12 is the sum of two composite numbers.

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If $n$ is even, then $n$ is the sum of $4$, which is composite, and $n-4$, which is even (a multiple of 2), hence composite, provided $n>6$.

If $n$ is odd, then $n$ is the sum of $9$, which is composite, and $n-9$, which is even (a multiple of 2), hence composite, provided $n>11.$