If $\bigtriangledown \times F=0,$ then $\exists $ a function $u$ such that $F= \bigtriangledown u$
The converse is straightforward to prove, but this statement is giving a hard time.
Any hints/tips/tricks?
Thank youuu!
If $\bigtriangledown \times F=0,$ then $\exists $ a function $u$ such that $F= \bigtriangledown u$
The converse is straightforward to prove, but this statement is giving a hard time.
Any hints/tips/tricks?
Thank youuu!
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