I studying the proof that the Petersen graph is not Hamiltonian, and in the proof, they used an observation that seems intuitively correct but I want to provide rigorous proof for it, given that I'm taking an introductory course to discrete mathematics.
Claim: Petersen graph has no cycles less than or equal to 4
I want to prove it by contradiction using the basics ideas, can you help me with that?
We can use a simple argument by coloring the edges of the Petersen's graph as shown below:
First note that there are 3 types of edges:
Now, since there is a blue cycle of length 5 with 5 outer blue nodes, it makes it impossible to have a blue monochrome cycle of length $\leq 4$, because
Using same argument we can show that we can't have an inner monochrome pink cycle of length $\leq 4$.
Also, a cycle which is not monochromatic must have a green edge (connecting an inner and an outer node). Now, in order to have a non-monochrome cycle of length $\leq 4$, we must have