Let $T$ be quadratic, invertible, symmetrical tridiagonal matrix and $Q$, $R$ matrices be $QR$ decomposition of $T$. Prove that $Q^{T}TQ$ is also symmetrical and tridiagonal.
The symmetric part is easy: $(Q^{T}TQ)^{T} = Q^{T}T^{T}Q = Q^{T}TQ$. I have no clue about how to prove it is tridiagonal.
$Q=TR^{-1}$ can only have one non-zero lower sub-diagonal, thus the same holds for $Q^TTQ=RQ$. Add symmetry.