Proving continuity for $2x+1$ at $x=2$ using epsilon/delta

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Problem

Use the epsilon/delta definition of continuity to show that $f(x) = 2x+1$ is continuous at $x=2$.

My work

The book shows an example using a similar, linear function, and while I can certainly do the same steps, I have a hard time groking it.

Let $h = x-2$, which gives $x = h+2$.

The allowed error is $|f(x) - f(2)| = |2h| = 2|h| < \varepsilon$ after skipping some steps, and substituting $x = h+2$.

Now comes the part I'm struggling to understand.

To satisfy $2|h| < \varepsilon$, I just need an $h \ \ \mid \ \ |h| < \frac{\varepsilon}2$. Done. Can do that for any $\varepsilon > 0$.

My actual question

What exactly is $\delta$ here? I can't fully understand why $h$ was introduced.

As far as I can tell, $|h| = \delta$, but why the extra variable?