So I'm set out to prove that for all $a,b\in\mathbb{R}^+$ where $a,b > 0$, and for all $r\in\mathbb{Q}$ where $r > 0$,
$$ a < b \quad \text{if and only if} \quad a^r<b^r $$
This seems so obvious that it shouldn't have to be proved, and thus I'm not really sure how to start.
The hint: $$b^r-a^r=a^r\left(\left(\frac{b}{a}\right)^r-1\right).$$