Let $u_n=v_n+ a4^{-n}n$ where $a$ is to be determined. You can plug this in, and choose $a=5$ to cancel out the $4^{-n}$ terms and only have recursive relation on $v_{n+1}$ and $v_n$.
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Multiplying both sides by $4^n$ will give you
$$4^{n+1}u_{n+1}-4^nu_n=5.$$
Let $x_n=4^nu_n$. The following is easy.
Let $u_n=v_n+ a4^{-n}n$ where $a$ is to be determined. You can plug this in, and choose $a=5$ to cancel out the $4^{-n}$ terms and only have recursive relation on $v_{n+1}$ and $v_n$.