I have a function $f:\mathbb{R}^n\to\mathbb{R}$ with normalized gradient $\widehat{\nabla f(x)}$ and Hessian $H(x)$ at the point $x\in\mathbb{R}^n$. I also know that $\widehat{y}$ is a unit vector perpendicular to the unit gradient $\widehat{y}\perp\widehat{\nabla f(x)}$. Can I say anything interesting about the following quadratic form? $$ \widehat{\nabla f(x)}^\top H(x) \widehat{y} $$ There is so much structure in this problem that there must be something special about this, perhaps a bound (assuming more things) or a nice expression.
2026-04-05 09:00:12.1775379612
Quadratic Form with perpendicular vectors
24 Views Asked by user318854 https://math.techqa.club/user/user318854/detail AtRelated Questions in CALCULUS
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